What is the answer to 4^{1-4x}=3^x ?

The answer to 4^{1-4x}=3^x is x=(2ln(2))/(ln(768))

Solve for x: 4^{1-4x}=3^x

The solution is x=(2ln(2))/(ln(768))

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4^{1 - 4 x} = 3^{x}

x = \frac{2 ln ( 2 )}{ln ( 768 )}

Decimal Notation

x = 0.20866 \dots

Solution steps

4^{1 - 4 x} = 3^{x}

Apply exponent rules

(1 - 4 x) ln (4) = x ln (3)

Solve

(1 - 4 x) ln (4) = x ln (3) : x = \frac{2 ln ( 2 )}{ln ( 768 )}

x = \frac{2 ln ( 2 )}{ln ( 768 )}

2^{(x + 4)} = \frac{1}{16}

4^{2 x + 1} \cdot 5^{x - 2} = 6^{1 - x}

x 9 = 8 + x + e^{x}

8^{- 9^{x^{- 1}}} = \frac{1}{2}

1.005 7^{4 t} = 2.22717

What is the answer to 4^{1-4x}=3^x ?
The answer to 4^{1-4x}=3^x is x=(2ln(2))/(ln(768))
Solve for x: 4^{1-4x}=3^x
The solution is x=(2ln(2))/(ln(768))