What is the answer to 2^{x-1}=400 ?

The answer to 2^{x-1}=400 is x=(2ln(20))/(ln(2))+1

Solve for x: 2^{x-1}=400

The solution is x=(2ln(20))/(ln(2))+1

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2^{x - 1} = 400

x = \frac{2 ln ( 20 )}{ln ( 2 )} + 1

Decimal Notation

x = 9.64385 \dots

Solution steps

2^{x - 1} = 400

Apply exponent rules

(x - 1) ln (2) = ln (400)

Solve

(x - 1) ln (2) = ln (400) : x = \frac{2 ln ( 20 )}{ln ( 2 )} + 1

x = \frac{2 ln ( 20 )}{ln ( 2 )} + 1

2^{x - 1} = (4^{2})^{x + 1}

2^{m + 1} = 1 6^{m + 7}

5^{3 x + 4} = 40

5^{3 x + 4} = 35

5^{3 x + 4} = 20

What is the answer to 2^{x-1}=400 ?
The answer to 2^{x-1}=400 is x=(2ln(20))/(ln(2))+1
Solve for x: 2^{x-1}=400
The solution is x=(2ln(20))/(ln(2))+1