What is the answer to 44000=26000(1.02)^{x(4)},x ?

The answer to 44000=26000(1.02)^{x(4)},x is x=(ln(22/13))/(4ln(1.02))

Solve for x: 44000=26000(1.02)^{x(4)},x

The solution is x=(ln(22/13))/(4ln(1.02))

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44000 = 26000 (1.02)^{x (4)}, x

x = \frac{ln ( \frac{22}{13} )}{4 ln ( 1.02 )}

Decimal Notation

x = 6.64170 \dots

Solution steps

44000 = 26000 (1.02)^{x (4)}

Switch sides

26000 \cdot 1.0 2^{x 4} = 44000

Divide both sides by

26000

1.0 2^{x 4} = \frac{22}{13}

Apply exponent rules

x \cdot 4 ln (1.02) = ln (\frac{22}{13})

Solve

x \cdot 4 ln (1.02) = ln (\frac{22}{13}) : x = \frac{ln ( \frac{22}{13} )}{4 ln ( 1.02 )}

x = \frac{ln ( \frac{22}{13} )}{4 ln ( 1.02 )}

10000 = 3500 (1.1)^{b}

x = 4^{x}

8^{x - 8} = 9

e^{x^{2}} - e^{5} e^{x - 1} = 0

11 (3 + e^{- x})^{- 1} = 2

What is the answer to 44000=26000(1.02)^{x(4)},x ?
The answer to 44000=26000(1.02)^{x(4)},x is x=(ln(22/13))/(4ln(1.02))
Solve for x: 44000=26000(1.02)^{x(4)},x
The solution is x=(ln(22/13))/(4ln(1.02))