What are the solutions to the equation x^2+x=60 ?

The solutions to the equation x^2+x=60 are x=(-1+sqrt(241))/2 ,x=(-1-sqrt(241))/2

Find the zeros of x^2+x=60

The zeros of x^2+x=60 are x=(-1+sqrt(241))/2 ,x=(-1-sqrt(241))/2

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x^{2} + x = 60

x = \frac{- 1 + 241}{2}, x = \frac{- 1 - 241}{2}

Decimal Notation

x = 7.26208 \dots, x = - 8.26208 \dots

Solution steps

x^{2} + x = 60

Move

60

to the left side

x^{2} + x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 60) = 241

x_{1, 2} = \frac{- 1 \pm 241}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 241}{2 \cdot 1}, x_{2} = \frac{- 1 - 241}{2 \cdot 1}

x = \frac{- 1 + 241}{2 \cdot 1} : \frac{- 1 + 241}{2}

x = \frac{- 1 - 241}{2 \cdot 1} : \frac{- 1 - 241}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 241}{2}, x = \frac{- 1 - 241}{2}

5 \leq x \leq 10

3 x - 15 = 6 x + 1

x^{2} - 2 x - \frac{3}{2} = 0

240 \cdot \frac{π}{180}

x^{2} + 2 x + 1 = - 15

What are the solutions to the equation x^2+x=60 ?
The solutions to the equation x^2+x=60 are x=(-1+sqrt(241))/2 ,x=(-1-sqrt(241))/2
Find the zeros of x^2+x=60
The zeros of x^2+x=60 are x=(-1+sqrt(241))/2 ,x=(-1-sqrt(241))/2