What is the answer to log_{10}(0.125^{x-2})=2 ?

The answer to log_{10}(0.125^{x-2})=2 is x=(2ln(10))/(ln(0.125))+2

Solve for x: log_{10}(0.125^{x-2})=2

The solution is x=(2ln(10))/(ln(0.125))+2

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lo g_{10} (0.12 5^{x - 2}) = 2

x = \frac{2 ln ( 10 )}{ln ( 0.125 )} + 2

Decimal Notation

x = - 0.21461 \dots

Solution steps

lo g_{10} (0.12 5^{x - 2}) = 2

Rewrite the equation with

0.12 5^{x - 2} = u

lo g_{10} (u) = 2

Solve

lo g_{10} (u) = 2 : u = 100

u = 100

Substitute back

u = 0.12 5^{x - 2},

solve for

x

Solve

0.12 5^{x - 2} = 100 : x = \frac{2 ln ( 10 )}{ln ( 0.125 )} + 2

x = \frac{2 ln ( 10 )}{ln ( 0.125 )} + 2

2^{x - 1} = 128

5^{x + 4} = 8

y, 1 5^{- 8 y} = 4

2 = (1 + 0.09)^{x}

9^{x} - 10 (9^{x}) + 9 = 0

What is the answer to log_{10}(0.125^{x-2})=2 ?
The answer to log_{10}(0.125^{x-2})=2 is x=(2ln(10))/(ln(0.125))+2
Solve for x: log_{10}(0.125^{x-2})=2
The solution is x=(2ln(10))/(ln(0.125))+2