What is the answer to 0=5^{x-1}-2 ?

The answer to 0=5^{x-1}-2 is x=(ln(2))/(ln(5))+1

Solve for x: 0=5^{x-1}-2

The solution is x=(ln(2))/(ln(5))+1

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0 = 5^{x - 1} - 2

x = \frac{ln ( 2 )}{ln ( 5 )} + 1

Decimal Notation

x = 1.43067 \dots

Solution steps

0 = 5^{x - 1} - 2

Add

2

to both sides

0 + 2 = 5^{x - 1} - 2 + 2

Simplify

2 = 5^{x - 1}

Apply exponent rules

ln (2) = (x - 1) ln (5)

Solve

ln (2) = (x - 1) ln (5) : x = \frac{ln ( 2 )}{ln ( 5 )} + 1

x = \frac{ln ( 2 )}{ln ( 5 )} + 1

5 = 100 e^{- 0.00043 t}

10 0^{x} - 1 0^{x} - 1 = 0

39 \cdot 1 0^{4 x} = 390

2^{3 x - 1} = 16

2000 \cdot e^{6 x} = 5000

What is the answer to 0=5^{x-1}-2 ?
The answer to 0=5^{x-1}-2 is x=(ln(2))/(ln(5))+1
Solve for x: 0=5^{x-1}-2
The solution is x=(ln(2))/(ln(5))+1