What is the answer to 6^{2x+1}=5^x ?

The answer to 6^{2x+1}=5^x is x=-(ln(6))/(2ln(6)-ln(5))

Solve for x: 6^{2x+1}=5^x

The solution is x=-(ln(6))/(2ln(6)-ln(5))

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6^{2 x + 1} = 5^{x}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

Decimal Notation

x = - 0.90764 \dots

Solution steps

6^{2 x + 1} = 5^{x}

Apply exponent rules

(2 x + 1) ln (6) = x ln (5)

Solve

(2 x + 1) ln (6) = x ln (5) : x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

\frac{1}{81} 3^{5 x + 1} = 81

8 (2)^{x} = 2^{x + 3}

ln (- 6) = ln (e^{\frac{1}{2} + c})

5^{x + 5} = 750

7^{y - 3} = 50

What is the answer to 6^{2x+1}=5^x ?
The answer to 6^{2x+1}=5^x is x=-(ln(6))/(2ln(6)-ln(5))
Solve for x: 6^{2x+1}=5^x
The solution is x=-(ln(6))/(2ln(6)-ln(5))