What is the answer to 7^{y-3}=50 ?

The answer to 7^{y-3}=50 is y=(ln(50))/(ln(7))+3

Solve for y: 7^{y-3}=50

The solution is y=(ln(50))/(ln(7))+3

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7^{y - 3} = 50

y = \frac{ln ( 50 )}{ln ( 7 )} + 3

Decimal Notation

y = 5.01038 \dots

Solution steps

7^{y - 3} = 50

Apply exponent rules

(y - 3) ln (7) = ln (50)

Solve

(y - 3) ln (7) = ln (50) : y = \frac{ln ( 50 )}{ln ( 7 )} + 3

y = \frac{ln ( 50 )}{ln ( 7 )} + 3

9^{x + 2} = 8 1^{5 x - 4}

204800 = 25 \cdot 2^{x}

ln (e^{2 x}) = 60

b, a^{2 b} = c

x, 6^{x + 2} = 5^{x - 2}

What is the answer to 7^{y-3}=50 ?
The answer to 7^{y-3}=50 is y=(ln(50))/(ln(7))+3
Solve for y: 7^{y-3}=50
The solution is y=(ln(50))/(ln(7))+3