What is the answer to (2/3)^x=2^{x-1} ?

The answer to (2/3)^x=2^{x-1} is x=(ln(2))/(ln(3))

Solve for x: (2/3)^x=2^{x-1}

The solution is x=(ln(2))/(ln(3))

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(\frac{2}{3})^{x} = 2^{x - 1}

x = \frac{ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 0.63092 \dots

Solution steps

(\frac{2}{3})^{x} = 2^{x - 1}

Apply exponent rules

x ln (\frac{2}{3}) = (x - 1) ln (2)

Solve

x ln (\frac{2}{3}) = (x - 1) ln (2) : x = \frac{ln ( 2 )}{ln ( 3 )}

x = \frac{ln ( 2 )}{ln ( 3 )}

4^{x} - 4^{\frac{( 2 x + 3 )}{2}} = - 7

27 (3^{2 x}) + 80 (3^{x}) - 3 = 0

x, e^{y - x^{2}} = 0

x, e^{y - x^{2}} = k

3^{x - 2} = 2^{x}

What is the answer to (2/3)^x=2^{x-1} ?
The answer to (2/3)^x=2^{x-1} is x=(ln(2))/(ln(3))
Solve for x: (2/3)^x=2^{x-1}
The solution is x=(ln(2))/(ln(3))