What is the answer to (3^x)^2-2*3^x-3=0 ?

The answer to (3^x)^2-2*3^x-3=0 is x=1

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(3^x)^2-2*3^x-3=0

(3^{x})^{2} - 2 \cdot 3^{x} - 3 = 0

x = 1

Solution steps

(3^{x})^{2} - 2 \cdot 3^{x} - 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 2 u - 3 = 0

Solve

u^{2} - 2 u - 3 = 0 : u = 3, u = - 1

u = 3, u = - 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = - 1 :

No Solution for

x \in R

x = 1

(\frac{1}{9})^{x} = 729

1 6^{- 7 x} = 72

5^{2 x - 1} = 6

5^{2 x + 4} = \frac{1}{625}

3^{x - 1} + 3^{x} - 12 = 0

What is the answer to (3^x)^2-2*3^x-3=0 ?
The answer to (3^x)^2-2*3^x-3=0 is x=1
Solve for x: (3^x)^2-2*3^x-3=0
The solution is x=1