What is the answer to 3^{x+1}+2(3^{x-1})=8 ?

The answer to 3^{x+1}+2(3^{x-1})=8 is x=(ln(8/11))/(ln(3))+1

Solve for x: 3^{x+1}+2(3^{x-1})=8

The solution is x=(ln(8/11))/(ln(3))+1

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3^{x + 1} + 2 (3^{x - 1}) = 8

x = \frac{ln ( \frac{8}{11} )}{ln ( 3 )} + 1

Decimal Notation

x = 0.71013 \dots

Solution steps

3^{x + 1} + 2 (3^{x - 1}) = 8

Factor

3^{x + 1} + 2 \cdot 3^{x - 1} : 11 \cdot 3^{x - 1}

11 \cdot 3^{x - 1} = 8

Divide both sides by

11

3^{x - 1} = \frac{8}{11}

Apply exponent rules

(x - 1) ln (3) = ln (\frac{8}{11})

Solve

(x - 1) ln (3) = ln (\frac{8}{11}) : x = \frac{ln ( \frac{8}{11} )}{ln ( 3 )} + 1

x = \frac{ln ( \frac{8}{11} )}{ln ( 3 )} + 1

3^{2 x} + 2 = 3^{x + 1}

0.7 5^{x} = 0.5

7^{x + 3} = 7^{2 x + 1}

9^{3 x + 1} = 2 7^{x + 2}

a lo g_{3} (4) = 2. 4^{- a}

What is the answer to 3^{x+1}+2(3^{x-1})=8 ?
The answer to 3^{x+1}+2(3^{x-1})=8 is x=(ln(8/11))/(ln(3))+1
Solve for x: 3^{x+1}+2(3^{x-1})=8
The solution is x=(ln(8/11))/(ln(3))+1