What is the answer to 9^{3x+1}=27^{x+2} ?

The answer to 9^{3x+1}=27^{x+2} is x= 4/3

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9^{3x+1}=27^{x+2}

9^{3 x + 1} = 2 7^{x + 2}

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

9^{3 x + 1} = 2 7^{x + 2}

Apply exponent rules

2 (3 x + 1) = 3 (x + 2)

Solve

2 (3 x + 1) = 3 (x + 2) : x = \frac{4}{3}

x = \frac{4}{3}

a lo g_{3} (4) = 2. 4^{- a}

7^{(- x + 4)} = 1

0.284 3^{x} = 70

9^{x - 1} = 7

3 e^{x} + 1 = 5

What is the answer to 9^{3x+1}=27^{x+2} ?
The answer to 9^{3x+1}=27^{x+2} is x= 4/3
Solve for x: 9^{3x+1}=27^{x+2}
The solution is x= 4/3