What is the answer to 33^{x+4}=9^{x+1} ?

The answer to 33^{x+4}=9^{x+1} is x=-(2ln(363))/(ln(11/3))

Solve for x: 33^{x+4}=9^{x+1}

The solution is x=-(2ln(363))/(ln(11/3))

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3 3^{x + 4} = 9^{x + 1}

x = - \frac{2 ln ( 363 )}{ln ( \frac{11}{3} )}

Decimal Notation

x = - 9.07331 \dots

Solution steps

3 3^{x + 4} = 9^{x + 1}

Apply exponent rules

(x + 4) ln (33) = (x + 1) ln (9)

Solve

(x + 4) ln (33) = (x + 1) ln (9) : x = - \frac{2 ln ( 363 )}{ln ( \frac{11}{3} )}

x = - \frac{2 ln ( 363 )}{ln ( \frac{11}{3} )}

8^{x + 5} = 1 6^{x}

446 = 1. 3^{x - 1}

2^{8} = 8^{x}

(3^{x + 1})^{2} = 8 1^{2 x - 4}

5^{2 x + 3} = 30

What is the answer to 33^{x+4}=9^{x+1} ?
The answer to 33^{x+4}=9^{x+1} is x=-(2ln(363))/(ln(11/3))
Solve for x: 33^{x+4}=9^{x+1}
The solution is x=-(2ln(363))/(ln(11/3))