What is the answer to 4^x=6^{x-2} ?

The answer to 4^x=6^{x-2} is x=(2ln(6))/(ln(3/2))

Solve for x: 4^x=6^{x-2}

The solution is x=(2ln(6))/(ln(3/2))

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4^{x} = 6^{x - 2}

x = \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

Decimal Notation

x = 8.83804 \dots

Solution steps

4^{x} = 6^{x - 2}

Apply exponent rules

x ln (4) = (x - 2) ln (6)

Solve

x ln (4) = (x - 2) ln (6) : x = \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

x = \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

2^{1 - x} + 4 = 9

(6^{3})^{x} = 6^{12}

e^{(- 0.25) x} = 0.98

e^{2 l n (3)} = 3^{1 - 2 x}

2 = e^{4 k}

What is the answer to 4^x=6^{x-2} ?
The answer to 4^x=6^{x-2} is x=(2ln(6))/(ln(3/2))
Solve for x: 4^x=6^{x-2}
The solution is x=(2ln(6))/(ln(3/2))