What is the answer to 2^{x-2}= 1/(4^{2-x)} ?

The answer to 2^{x-2}= 1/(4^{2-x)} is x=2

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2^{x-2}= 1/(4^{2-x)}

2^{x - 2} = \frac{1}{4 ^{2 - x}}

x = 2

Solution steps

2^{x - 2} = \frac{1}{4 ^{2 - x}}

Apply exponent rules

x - 2 = 2 (- 2 + x)

Solve

x - 2 = 2 (- 2 + x) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

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8^{x - 1} = \frac{1}{16}

0.21 = (1.3384) e^{2.558 x}

2^{2 x - 1} - 6 \cdot 2^{x - 1} = 0

x, 2^{- x} = 0

What is the answer to 2^{x-2}= 1/(4^{2-x)} ?
The answer to 2^{x-2}= 1/(4^{2-x)} is x=2
Solve for x: 2^{x-2}= 1/(4^{2-x)}
The solution is x=2