What is the answer to 1/(3^{x-1)}=\sqrt[3]{9} ?

The answer to 1/(3^{x-1)}=\sqrt[3]{9} is x= 1/3

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1/(3^{x-1)}=\sqrt[3]{9}

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

Apply exponent rules

- x + 1 = \frac{2}{3}

Solve

- x + 1 = \frac{2}{3} : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

N, F = P \cdot (1 + x)^{N}

2^{x} + 1 = 2 x + 5

1 6^{x} = \frac{1}{2}

45 = 3 0^{x^{6}}

y, x = e^{1 - y}

What is the answer to 1/(3^{x-1)}=\sqrt[3]{9} ?
The answer to 1/(3^{x-1)}=\sqrt[3]{9} is x= 1/3
Solve for x: 1/(3^{x-1)}=\sqrt[3]{9}
The solution is x= 1/3