What is the answer to 2^{x+1}=3(5^x) ?

The answer to 2^{x+1}=3(5^x) is x=(ln(3)-ln(2))/(ln(2)-ln(5))

Solve for x: 2^{x+1}=3(5^x)

The solution is x=(ln(3)-ln(2))/(ln(2)-ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x + 1} = 3 (5^{x})

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = - 0.44250 \dots

Solution steps

2^{x + 1} = 3 (5^{x})

Apply exponent rules

(x + 1) ln (2) = ln (3) + x ln (5)

Solve

(x + 1) ln (2) = ln (3) + x ln (5) : x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - ln ( 5 )}

\frac{1}{e ^{t}} = e^{- t}

x, x^{2} = 2^{x}

0.08 = \frac{20}{2 ^{x}}

10 0^{x} = (\frac{1}{10})^{x - 3}

lo g_{3} (5^{7 x}) = 12

What is the answer to 2^{x+1}=3(5^x) ?
The answer to 2^{x+1}=3(5^x) is x=(ln(3)-ln(2))/(ln(2)-ln(5))
Solve for x: 2^{x+1}=3(5^x)
The solution is x=(ln(3)-ln(2))/(ln(2)-ln(5))