What is the answer to 0.08=(20)/(2^x) ?

The answer to 0.08=(20)/(2^x) is x=-(ln(0.004))/(ln(2))

Solve for x: 0.08=(20)/(2^x)

The solution is x=-(ln(0.004))/(ln(2))

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0.08 = \frac{20}{2 ^{x}}

x = - \frac{ln ( 0.004 )}{ln ( 2 )}

Decimal Notation

x = 7.96578 \dots

Solution steps

0.08 = \frac{20}{2 ^{x}}

Apply exponent rules

- x ln (2) = ln (0.004)

Solve

- x ln (2) = ln (0.004) : x = - \frac{ln ( 0.004 )}{ln ( 2 )}

x = - \frac{ln ( 0.004 )}{ln ( 2 )}

Verify Solutions:

x = - \frac{ln ( 0.004 )}{ln ( 2 )}

True

The solution is

x = - \frac{ln ( 0.004 )}{ln ( 2 )}

10 0^{x} = (\frac{1}{10})^{x - 3}

lo g_{3} (5^{7 x}) = 12

(x - 3)^{5 x + 1} = (x - 3)^{x^{2} - 5}

3^{2 x + 2} + 8 (3)^{x + 1} = 9

4^{x + 3} = 4^{9}

What is the answer to 0.08=(20)/(2^x) ?
The answer to 0.08=(20)/(2^x) is x=-(ln(0.004))/(ln(2))
Solve for x: 0.08=(20)/(2^x)
The solution is x=-(ln(0.004))/(ln(2))