What is the answer to (x-3)^{5x+1}=(x-3)^{x^2-5} ?

The answer to (x-3)^{5x+1}=(x-3)^{x^2-5} is x=4,x=6

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(x-3)^{5x+1}=(x-3)^{x^2-5}

(x - 3)^{5 x + 1} = (x - 3)^{x^{2} - 5}

x = 4, x = 6

Solution steps

(x - 3)^{5 x + 1} = (x - 3)^{x^{2} - 5}

Apply exponent rules

(5 x + 1) ln (x - 3) = (x^{2} - 5) ln (x - 3)

Solve

(5 x + 1) ln (x - 3) = (x^{2} - 5) ln (x - 3) : x = 4, x = 6

x = 4, x = 6

3^{2 x + 2} + 8 (3)^{x + 1} = 9

4^{x + 3} = 4^{9}

2 = 1.042 5^{x}

3 3^{x - 2} = 1 7^{8 x}

57 = 2 7^{x}

What is the answer to (x-3)^{5x+1}=(x-3)^{x^2-5} ?
The answer to (x-3)^{5x+1}=(x-3)^{x^2-5} is x=4,x=6
Solve for x: (x-3)^{5x+1}=(x-3)^{x^2-5}
The solution is x=4,x=6