What is the answer to 6^{2+2}=7^{x-1} ?

The answer to 6^{2+2}=7^{x-1} is x=(4ln(6))/(ln(7))+1

Solve for x: 6^{2+2}=7^{x-1}

The solution is x=(4ln(6))/(ln(7))+1

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6^{2 + 2} = 7^{x - 1}

x = \frac{4 ln ( 6 )}{ln ( 7 )} + 1

Decimal Notation

x = 4.68312 \dots

Solution steps

6^{2 + 2} = 7^{x - 1}

Apply exponent rules

(2 + 2) ln (6) = (x - 1) ln (7)

Solve

(2 + 2) ln (6) = (x - 1) ln (7) : x = \frac{4 ln ( 6 )}{ln ( 7 )} + 1

x = \frac{4 ln ( 6 )}{ln ( 7 )} + 1

6^{3 - 2 x} = 36

2^{4 x + 3} = 10

5^{3 x - 1} - 4^{x + 1} = 0

2^{x} - 2^{1 - x} + 2^{0} = 0

e^{x} = 6^{x + 4}

What is the answer to 6^{2+2}=7^{x-1} ?
The answer to 6^{2+2}=7^{x-1} is x=(4ln(6))/(ln(7))+1
Solve for x: 6^{2+2}=7^{x-1}
The solution is x=(4ln(6))/(ln(7))+1