What is the answer to 5^{x+4}=4^{x+5} ?

The answer to 5^{x+4}=4^{x+5} is x=(10ln(2)-4ln(5))/(ln(5)-2ln(2))

Solve for x: 5^{x+4}=4^{x+5}

The solution is x=(10ln(2)-4ln(5))/(ln(5)-2ln(2))

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5^{x + 4} = 4^{x + 5}

x = \frac{10 ln ( 2 ) - 4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

Decimal Notation

x = 2.21256 \dots

Solution steps

5^{x + 4} = 4^{x + 5}

Apply exponent rules

(x + 4) ln (5) = (x + 5) ln (4)

Solve

(x + 4) ln (5) = (x + 5) ln (4) : x = \frac{10 ln ( 2 ) - 4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

x = \frac{10 ln ( 2 ) - 4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

7^{0.3 x} = 813

e^{- x} x^{2} + 2 e^{- x} x - e^{- x} = 0

(\frac{1}{8})^{x - 3} = 1 6^{4 x - 3}

2^{k - 2} \cdot 5^{k - 2} = 100

5^{x + 5} = 7

What is the answer to 5^{x+4}=4^{x+5} ?
The answer to 5^{x+4}=4^{x+5} is x=(10ln(2)-4ln(5))/(ln(5)-2ln(2))
Solve for x: 5^{x+4}=4^{x+5}
The solution is x=(10ln(2)-4ln(5))/(ln(5)-2ln(2))