What is the answer to 4(3)^{x+2}=72 ?

The answer to 4(3)^{x+2}=72 is x=(ln(18))/(ln(3))-2

Solve for x: 4(3)^{x+2}=72

The solution is x=(ln(18))/(ln(3))-2

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4 (3)^{x + 2} = 72

x = \frac{ln ( 18 )}{ln ( 3 )} - 2

Decimal Notation

x = 0.63092 \dots

Solution steps

4 (3)^{x + 2} = 72

Divide both sides by

4

3^{x + 2} = 18

Apply exponent rules

(x + 2) ln (3) = ln (18)

Solve

(x + 2) ln (3) = ln (18) : x = \frac{ln ( 18 )}{ln ( 3 )} - 2

x = \frac{ln ( 18 )}{ln ( 3 )} - 2

\frac{3}{4} \cdot 2^{n - 2} = 768

204.6 = 0.2 (\frac{1 - 2 ^{x}}{1 - 2})

1.02 = 1 - 2 e^{- x} + e^{- 0.5 x}

2 e^{2 x} - 2 = 0

7^{3 x + 4} = 42

What is the answer to 4(3)^{x+2}=72 ?
The answer to 4(3)^{x+2}=72 is x=(ln(18))/(ln(3))-2
Solve for x: 4(3)^{x+2}=72
The solution is x=(ln(18))/(ln(3))-2