What is the answer to 7^{3x+4}=42 ?

The answer to 7^{3x+4}=42 is x=(ln(6/343))/(3ln(7))

Solve for x: 7^{3x+4}=42

The solution is x=(ln(6/343))/(3ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{3 x + 4} = 42

x = \frac{ln ( \frac{6}{343} )}{3 ln ( 7 )}

Decimal Notation

x = - 0.69307 \dots

Solution steps

7^{3 x + 4} = 42

Apply exponent rules

(3 x + 4) ln (7) = ln (42)

Solve

(3 x + 4) ln (7) = ln (42) : x = \frac{ln ( \frac{6}{343} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{6}{343} )}{3 ln ( 7 )}

t^{2} e^{t} + 2 t e^{t} - 8 e^{t} = 0

ln (\frac{8}{e ^{4 x}}) = 24

9^{2 x - 1} = \frac{1}{81}

e^{m x} (m^{2} + 6 m + 5) = 0

4^{8^{3 + 2 x}} = 2^{2^{7 x - 1}}

What is the answer to 7^{3x+4}=42 ?
The answer to 7^{3x+4}=42 is x=(ln(6/343))/(3ln(7))
Solve for x: 7^{3x+4}=42
The solution is x=(ln(6/343))/(3ln(7))