What is the answer to 3^x=sqrt(6) ?

The answer to 3^x=sqrt(6) is x=(ln(6))/(2ln(3))

Solve for x: 3^x=sqrt(6)

The solution is x=(ln(6))/(2ln(3))

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3^{x} = 6

x = \frac{ln ( 6 )}{2 ln ( 3 )}

Decimal Notation

x = 0.81546 \dots

Solution steps

3^{x} = 6

Apply exponent rules

x ln (3) = \frac{1}{2} ln (6)

Solve

x ln (3) = \frac{1}{2} ln (6) : x = \frac{ln ( 6 )}{2 ln ( 3 )}

x = \frac{ln ( 6 )}{2 ln ( 3 )}

400 = 250 (1 + 0.07)^{t}

28 \cdot 1 3^{x + 11} - 16 = 12

\frac{30}{1 + e ^{- x}} = 4

\frac{2 ^{x} - 2}{4} = 1 + 2^{2 - x}

7^{x + 3} = 5

What is the answer to 3^x=sqrt(6) ?
The answer to 3^x=sqrt(6) is x=(ln(6))/(2ln(3))
Solve for x: 3^x=sqrt(6)
The solution is x=(ln(6))/(2ln(3))