What is the answer to 3^{4x}=7^{x^2} ?

The answer to 3^{4x}=7^{x^2} is x=0,x=(4ln(3))/(ln(7))

Solve for x: 3^{4x}=7^{x^2}

The solution is x=0,x=(4ln(3))/(ln(7))

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3^{4 x} = 7^{x^{2}}

x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

Decimal Notation

x = 0, x = 2.25830 \dots

Solution steps

3^{4 x} = 7^{x^{2}}

Apply exponent rules

4 x ln (3) = x^{2} ln (7)

Solve

4 x ln (3) = x^{2} ln (7) : x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

5^{x^{2}} = 2 5^{3 x - 4}

8^{x - 2} = 125

(\frac{1}{3})^{x + 2} = 3 x + 1

1 5^{4 x} = 8^{x - 9}

What is the answer to 3^{4x}=7^{x^2} ?
The answer to 3^{4x}=7^{x^2} is x=0,x=(4ln(3))/(ln(7))
Solve for x: 3^{4x}=7^{x^2}
The solution is x=0,x=(4ln(3))/(ln(7))