What is the answer to solvefor x,e^{-2x}-e^{2y}=c ?

The answer to solvefor x,e^{-2x}-e^{2y}=c is x=-(ln(c+e^{2y}))/2

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solvefor x,e^{-2x}-e^{2y}=c

solve for

x, e^{- 2 x} - e^{2 y} = c

x = - \frac{ln ( c + e ^{2 y} )}{2}

Solution steps

e^{- 2 x} - e^{2 y} = c

Move

e^{2 y}

to the right side

e^{- 2 x} = c + e^{2 y}

Apply exponent rules

- 2 x = ln (c + e^{2 y})

Solve

- 2 x = ln (c + e^{2 y}) : x = - \frac{ln ( c + e ^{2 y} )}{2}

x = - \frac{ln ( c + e ^{2 y} )}{2}

y, x = 4^{7^{y}}

(5^{x})^{2} = 625

x, 5^{x - 6} = 7

5^{2 t + 1} - 26 \cdot 5^{t} + 5 = 0

What is the answer to solvefor x,e^{-2x}-e^{2y}=c ?
The answer to solvefor x,e^{-2x}-e^{2y}=c is x=-(ln(c+e^{2y}))/2