What is the answer to solvefor y,x=4^{7^y} ?

The answer to solvefor y,x=4^{7^y} is y=(ln(\frac{ln(x))/(2ln(2)))}{ln(7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,x=4^{7^y}

solve for

y, x = 4^{7^{y}}

y = \frac{ln ( \frac{l n ( x )}{2 l n ( 2 )} )}{ln ( 7 )}

Solution steps

x = 4^{7^{y}}

Apply exponent rules

y ln (7) = ln (\frac{ln ( x )}{2 ln ( 2 )})

Solve

y ln (7) = ln (\frac{ln ( x )}{2 ln ( 2 )}) : y = \frac{ln ( \frac{l n ( x )}{2 l n ( 2 )} )}{ln ( 7 )}

y = \frac{ln ( \frac{l n ( x )}{2 l n ( 2 )} )}{ln ( 7 )}

(5^{x})^{2} = 625

x, 5^{x - 6} = 7

5^{2 t + 1} - 26 \cdot 5^{t} + 5 = 0

What is the answer to solvefor y,x=4^{7^y} ?
The answer to solvefor y,x=4^{7^y} is y=(ln(\frac{ln(x))/(2ln(2)))}{ln(7)}