What is the answer to \sqrt[4]{\sqrt[3]{9}}=3^x ?

The answer to \sqrt[4]{\sqrt[3]{9}}=3^x is x= 1/6

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\sqrt[4]{\sqrt[3]{9}}=3^x

x = \frac{1}{6}

Decimal Notation

x = 0.16666 \dots

Solution steps

Apply exponent rules

\frac{1}{6} = x

Switch sides

x = \frac{1}{6}

2^{x^{2} - x + 3} = 32

3^{2 x + 5} = 7^{x}

e^{4 x} = \frac{1}{64}

7^{- 3 x} = 1 1^{x + 8}

3^{x} = - 2 in

What is the answer to \sqrt[4]{\sqrt[3]{9}}=3^x ?
The answer to \sqrt[4]{\sqrt[3]{9}}=3^x is x= 1/6
Solve for x: \sqrt[4]{\sqrt[3]{9}}=3^x
The solution is x= 1/6