What is the answer to 3^{2x+5}=7^x ?

The answer to 3^{2x+5}=7^x is x=-(5ln(3))/(2ln(3)-ln(7))

Solve for x: 3^{2x+5}=7^x

The solution is x=-(5ln(3))/(2ln(3)-ln(7))

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3^{2 x + 5} = 7^{x}

x = - \frac{5 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

Decimal Notation

x = - 21.85732 \dots

Solution steps

3^{2 x + 5} = 7^{x}

Apply exponent rules

(2 x + 5) ln (3) = x ln (7)

Solve

(2 x + 5) ln (3) = x ln (7) : x = - \frac{5 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

x = - \frac{5 ln ( 3 )}{2 ln ( 3 ) - ln ( 7 )}

e^{4 x} = \frac{1}{64}

7^{- 3 x} = 1 1^{x + 8}

3^{x} = - 2 in

7^{- x} = 2

2^{3 y} - 2^{2 y} - 2^{y + 1} = 0

What is the answer to 3^{2x+5}=7^x ?
The answer to 3^{2x+5}=7^x is x=-(5ln(3))/(2ln(3)-ln(7))
Solve for x: 3^{2x+5}=7^x
The solution is x=-(5ln(3))/(2ln(3)-ln(7))