What is the answer to 7^{-3x}=11^{x+8} ?

The answer to 7^{-3x}=11^{x+8} is x=-(8ln(11))/(ln(3773))

Solve for x: 7^{-3x}=11^{x+8}

The solution is x=-(8ln(11))/(ln(3773))

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7^{- 3 x} = 1 1^{x + 8}

x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

Decimal Notation

x = - 2.32929 \dots

Solution steps

7^{- 3 x} = 1 1^{x + 8}

Apply exponent rules

- 3 x ln (7) = (x + 8) ln (11)

Solve

- 3 x ln (7) = (x + 8) ln (11) : x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

3^{x} = - 2 in

7^{- x} = 2

2^{3 y} - 2^{2 y} - 2^{y + 1} = 0

x, ln (y) = e^{x} + ln (2)

u, y = x^{u}

What is the answer to 7^{-3x}=11^{x+8} ?
The answer to 7^{-3x}=11^{x+8} is x=-(8ln(11))/(ln(3773))
Solve for x: 7^{-3x}=11^{x+8}
The solution is x=-(8ln(11))/(ln(3773))