What is the answer to 7^x=0.5^{x-1} ?

The answer to 7^x=0.5^{x-1} is x=-(ln(0.5))/(ln(7)-ln(0.5))

Solve for x: 7^x=0.5^{x-1}

The solution is x=-(ln(0.5))/(ln(7)-ln(0.5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{x} = 0. 5^{x - 1}

x = - \frac{ln ( 0.5 )}{ln ( 7 ) - ln ( 0.5 )}

Decimal Notation

x = 0.26264 \dots

Solution steps

7^{x} = 0. 5^{x - 1}

Apply exponent rules

x ln (7) = (x - 1) ln (0.5)

Solve

x ln (7) = (x - 1) ln (0.5) : x = - \frac{ln ( 0.5 )}{ln ( 7 ) - ln ( 0.5 )}

x = - \frac{ln ( 0.5 )}{ln ( 7 ) - ln ( 0.5 )}

\frac{1}{1 0 ^{3}} = 1 0^{x}

x^{2} 2^{x} - 2^{x} 7 = 0

5^{3 - 2 x} = 4 (7^{x})

e^{x} x^{2} = 0

lo g_{5} (5^{x}) = 2

What is the answer to 7^x=0.5^{x-1} ?
The answer to 7^x=0.5^{x-1} is x=-(ln(0.5))/(ln(7)-ln(0.5))
Solve for x: 7^x=0.5^{x-1}
The solution is x=-(ln(0.5))/(ln(7)-ln(0.5))