What is the answer to 5^{2x-8}=7^{2x-8} ?

The answer to 5^{2x-8}=7^{2x-8} is x=-(8ln(7)-8ln(5))/(2(ln(5)-ln(7)))

Solve for x: 5^{2x-8}=7^{2x-8}

The solution is x=-(8ln(7)-8ln(5))/(2(ln(5)-ln(7)))

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5^{2 x - 8} = 7^{2 x - 8}

x = - \frac{8 ln ( 7 ) - 8 ln ( 5 )}{2 ( ln ( 5 ) - ln ( 7 ) )}

Decimal Notation

x = 4

Solution steps

5^{2 x - 8} = 7^{2 x - 8}

Apply exponent rules

(2 x - 8) ln (5) = (2 x - 8) ln (7)

Solve

(2 x - 8) ln (5) = (2 x - 8) ln (7) : x = - \frac{8 ln ( 7 ) - 8 ln ( 5 )}{2 ( ln ( 5 ) - ln ( 7 ) )}

x = - \frac{8 ln ( 7 ) - 8 ln ( 5 )}{2 ( ln ( 5 ) - ln ( 7 ) )}

(2)^{x} = 42

75 = 1.0 1^{x}

n, (1 + i)^{n} = i

77 = 1 7^{x}

40 = 20 (1 0^{0.1 x})

What is the answer to 5^{2x-8}=7^{2x-8} ?
The answer to 5^{2x-8}=7^{2x-8} is x=-(8ln(7)-8ln(5))/(2(ln(5)-ln(7)))
Solve for x: 5^{2x-8}=7^{2x-8}
The solution is x=-(8ln(7)-8ln(5))/(2(ln(5)-ln(7)))