What is the answer to 40=20(10^{0.1x}) ?

The answer to 40=20(10^{0.1x}) is x=(ln(2))/(0.1ln(10))

Solve for x: 40=20(10^{0.1x})

The solution is x=(ln(2))/(0.1ln(10))

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40 = 20 (1 0^{0.1 x})

x = \frac{ln ( 2 )}{0.1 ln ( 10 )}

Decimal Notation

x = 3.01029 \dots

Solution steps

40 = 20 (1 0^{0.1 x})

Switch sides

20 \cdot 1 0^{0.1 x} = 40

Divide both sides by

20

1 0^{0.1 x} = 2

Apply exponent rules

0.1 x ln (10) = ln (2)

Solve

0.1 x ln (10) = ln (2) : x = \frac{ln ( 2 )}{0.1 ln ( 10 )}

x = \frac{ln ( 2 )}{0.1 ln ( 10 )}

2^{3 x + 5} = 2^{1 - x}

e^{\frac{k}{6}} = a

1 0^{x} = 3588

(x)^{- 1 + l o g_{2} (x)} = 2

55 = 5 + c e^{(\frac{l n ( 50 )}{c})}

What is the answer to 40=20(10^{0.1x}) ?
The answer to 40=20(10^{0.1x}) is x=(ln(2))/(0.1ln(10))
Solve for x: 40=20(10^{0.1x})
The solution is x=(ln(2))/(0.1ln(10))