What is the answer to 2^{x-1}5^{2x-3}=4 ?

The answer to 2^{x-1}5^{2x-3}=4 is x=(3+3log_{2}(5))/(1+2log_{2)(5)}

Solve for x: 2^{x-1}5^{2x-3}=4

The solution is x=(3+3log_{2}(5))/(1+2log_{2)(5)}

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2^{x - 1} 5^{2 x - 3} = 4

x = \frac{3 + 3 lo g _{2} ( 5 )}{1 + 2 lo g _{2} ( 5 )}

Decimal Notation

x = 1.76577 \dots

Solution steps

2^{x - 1} \cdot 5^{2 x - 3} = 4

Apply exponent rules

x - 1 + lo g_{2} (5) (2 x - 3) = 2

Solve

x - 1 + lo g_{2} (5) (2 x - 3) = 2 : x = \frac{3 + 3 lo g _{2} ( 5 )}{1 + 2 lo g _{2} ( 5 )}

x = \frac{3 + 3 lo g _{2} ( 5 )}{1 + 2 lo g _{2} ( 5 )}

r, 4 = e^{8 r}

2^{x + 7} = 2^{1 - 2 x}

(4 x)^{4 x} = 2^{24}

x, g^{x + 3} = 8 1^{3 x - 7}

e^{- x} - e^{x} = 0

What is the answer to 2^{x-1}5^{2x-3}=4 ?
The answer to 2^{x-1}5^{2x-3}=4 is x=(3+3log_{2}(5))/(1+2log_{2)(5)}
Solve for x: 2^{x-1}5^{2x-3}=4
The solution is x=(3+3log_{2}(5))/(1+2log_{2)(5)}