What is the answer to solvefor x,g^{x+3}=81^{3x-7} ?

The answer to solvefor x,g^{x+3}=81^{3x-7} is x=-(ln(81^7g^3))/(ln(g)-12ln(3))

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solvefor x,g^{x+3}=81^{3x-7}

solve for

x, g^{x + 3} = 8 1^{3 x - 7}

x = - \frac{ln ( 8 1 ^{7} g ^{3} )}{ln ( g ) - 12 ln ( 3 )}

Solution steps

g^{x + 3} = 8 1^{3 x - 7}

Apply exponent rules

(x + 3) ln (g) = (3 x - 7) ln (81)

Solve

(x + 3) ln (g) = (3 x - 7) ln (81) : x = - \frac{ln ( 8 1 ^{7} g ^{3} )}{ln ( g ) - 12 ln ( 3 )}

x = - \frac{ln ( 8 1 ^{7} g ^{3} )}{ln ( g ) - 12 ln ( 3 )}

e^{- x} - e^{x} = 0

x, 12 5^{x} - 5 = 0

3^{x} + 2 \cdot 3^{x} = 3^{x + 1}

n, 1 = x^{n}

5^{2 x - 5} = 1 0^{x + 1}

What is the answer to solvefor x,g^{x+3}=81^{3x-7} ?
The answer to solvefor x,g^{x+3}=81^{3x-7} is x=-(ln(81^7g^3))/(ln(g)-12ln(3))