What is the answer to 5^{2x-5}=10^{x+1} ?

The answer to 5^{2x-5}=10^{x+1} is x=(ln(10)+5ln(5))/(ln(5/2))

Solve for x: 5^{2x-5}=10^{x+1}

The solution is x=(ln(10)+5ln(5))/(ln(5/2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2 x - 5} = 1 0^{x + 1}

x = \frac{ln ( 10 ) + 5 ln ( 5 )}{ln ( \frac{5}{2} )}

Decimal Notation

x = 11.29529 \dots

Solution steps

5^{2 x - 5} = 1 0^{x + 1}

Apply exponent rules

(2 x - 5) ln (5) = (x + 1) ln (10)

Solve

(2 x - 5) ln (5) = (x + 1) ln (10) : x = \frac{ln ( 10 ) + 5 ln ( 5 )}{ln ( \frac{5}{2} )}

x = \frac{ln ( 10 ) + 5 ln ( 5 )}{ln ( \frac{5}{2} )}

3 = (1 + 0.15)^{n}

1 0^{2^{x}} = 5

1200 = 6 \cdot 3^{t}

1 0^{\frac{x}{4}} = 8

\frac{k ^{x + 3}}{k ^{3 x}} = k^{x}

What is the answer to 5^{2x-5}=10^{x+1} ?
The answer to 5^{2x-5}=10^{x+1} is x=(ln(10)+5ln(5))/(ln(5/2))
Solve for x: 5^{2x-5}=10^{x+1}
The solution is x=(ln(10)+5ln(5))/(ln(5/2))