What is the answer to 3^{7x-2}=4^{x+3} ?

The answer to 3^{7x-2}=4^{x+3} is x=(2ln(24))/(7ln(3)-2ln(2))

Solve for x: 3^{7x-2}=4^{x+3}

The solution is x=(2ln(24))/(7ln(3)-2ln(2))

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3^{7 x - 2} = 4^{x + 3}

x = \frac{2 ln ( 24 )}{7 ln ( 3 ) - 2 ln ( 2 )}

Decimal Notation

x = 1.00826 \dots

Solution steps

3^{7 x - 2} = 4^{x + 3}

Apply exponent rules

(7 x - 2) ln (3) = (x + 3) ln (4)

Solve

(7 x - 2) ln (3) = (x + 3) ln (4) : x = \frac{2 ln ( 24 )}{7 ln ( 3 ) - 2 ln ( 2 )}

x = \frac{2 ln ( 24 )}{7 ln ( 3 ) - 2 ln ( 2 )}

3276 8^{- x + 11} = 6 4^{4 x + 2}

0.6 4^{t} = \frac{1}{10}

3^{x} = 19683

2^{2 x + 4} = 1

68.6 = 41.8 e^{k (2029 - 2005)}

What is the answer to 3^{7x-2}=4^{x+3} ?
The answer to 3^{7x-2}=4^{x+3} is x=(2ln(24))/(7ln(3)-2ln(2))
Solve for x: 3^{7x-2}=4^{x+3}
The solution is x=(2ln(24))/(7ln(3)-2ln(2))