What is the answer to 3*5^x=7*29^x ?

The answer to 3*5^x=7*29^x is x=(ln(7)-ln(3))/(ln(5)-ln(29))

Solve for x: 3*5^x=7*29^x

The solution is x=(ln(7)-ln(3))/(ln(5)-ln(29))

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3 \cdot 5^{x} = 7 \cdot 2 9^{x}

x = \frac{ln ( 7 ) - ln ( 3 )}{ln ( 5 ) - ln ( 29 )}

Decimal Notation

x = - 0.48200 \dots

Solution steps

3 \cdot 5^{x} = 7 \cdot 2 9^{x}

Apply exponent rules

ln (3) + x ln (5) = ln (7) + x ln (29)

Solve

ln (3) + x ln (5) = ln (7) + x ln (29) : x = \frac{ln ( 7 ) - ln ( 3 )}{ln ( 5 ) - ln ( 29 )}

x = \frac{ln ( 7 ) - ln ( 3 )}{ln ( 5 ) - ln ( 29 )}

9^{x} = e^{x + 4}

(2^{x})^{2} - 5 (2^{x}) + 4 = 0

8^{- 4 x} = 1 3^{x + 4}

5^{2 x} - 2 (5^{x}) = 15

9^{x} = e^{x + 9}

What is the answer to 3*5^x=7*29^x ?
The answer to 3*5^x=7*29^x is x=(ln(7)-ln(3))/(ln(5)-ln(29))
Solve for x: 3*5^x=7*29^x
The solution is x=(ln(7)-ln(3))/(ln(5)-ln(29))