What is the answer to 7^{2x+5}=5*(3^{3x}) ?

The answer to 7^{2x+5}=5*(3^{3x}) is x=(ln(5)-5ln(7))/(2ln(7)-3ln(3))

Solve for x: 7^{2x+5}=5*(3^{3x})

The solution is x=(ln(5)-5ln(7))/(2ln(7)-3ln(3))

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7^{2 x + 5} = 5 \cdot (3^{3 x})

x = \frac{ln ( 5 ) - 5 ln ( 7 )}{2 ln ( 7 ) - 3 ln ( 3 )}

Decimal Notation

x = - 13.62472 \dots

Solution steps

7^{2 x + 5} = 5 (3^{3 x})

Apply exponent rules

(2 x + 5) ln (7) = ln (5) + 3 x ln (3)

Solve

(2 x + 5) ln (7) = ln (5) + 3 x ln (3) : x = \frac{ln ( 5 ) - 5 ln ( 7 )}{2 ln ( 7 ) - 3 ln ( 3 )}

x = \frac{ln ( 5 ) - 5 ln ( 7 )}{2 ln ( 7 ) - 3 ln ( 3 )}

2^{x} = \frac{4 ^{x - 2}}{8}

6 e^{1 - x} + 1 = 25

1500000 = 3 (2^{x - 1})

e^{- 4 x} = (e^{8})^{1 - x}

3^{6 x - 2} = (3^{x + 3})^{2}

What is the answer to 7^{2x+5}=5*(3^{3x}) ?
The answer to 7^{2x+5}=5*(3^{3x}) is x=(ln(5)-5ln(7))/(2ln(7)-3ln(3))
Solve for x: 7^{2x+5}=5*(3^{3x})
The solution is x=(ln(5)-5ln(7))/(2ln(7)-3ln(3))