What are the solutions to the equation 12x^3+8x^2-x-1=0 ?

The solutions to the equation 12x^3+8x^2-x-1=0 are x=-1/2 ,x= 1/3

Find the zeros of 12x^3+8x^2-x-1=0

The zeros of 12x^3+8x^2-x-1=0 are x=-1/2 ,x= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{3} + 8 x^{2} - x - 1 = 0

x = - \frac{1}{2}, x = \frac{1}{3}

Solution steps

12 x^{3} + 8 x^{2} - x - 1 = 0

Factor

12 x^{3} + 8 x^{2} - x - 1 : (2 x + 1)^{2} (3 x - 1)

(2 x + 1)^{2} (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 3 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions are

x = - \frac{1}{2}, x = \frac{1}{3}

x^{3} + 2 x^{2} - 4 x - 8 = 0

z^{4} - 16 = 0

x^{4} - 20 x^{2} + 64 = 0

2 x^{4} + 5 x^{3} + 4 = x^{2}

x^{4} - 34 x^{2} + 225 = 0

What are the solutions to the equation 12x^3+8x^2-x-1=0 ?
The solutions to the equation 12x^3+8x^2-x-1=0 are x=-1/2 ,x= 1/3
Find the zeros of 12x^3+8x^2-x-1=0
The zeros of 12x^3+8x^2-x-1=0 are x=-1/2 ,x= 1/3