What are the solutions to the equation x^3+2x^2-4x-8=0 ?

The solutions to the equation x^3+2x^2-4x-8=0 are x=-2,x=2

Find the zeros of x^3+2x^2-4x-8=0

The zeros of x^3+2x^2-4x-8=0 are x=-2,x=2

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x^{3} + 2 x^{2} - 4 x - 8 = 0

x = - 2, x = 2

Solution steps

x^{3} + 2 x^{2} - 4 x - 8 = 0

Factor

x^{3} + 2 x^{2} - 4 x - 8 : (x + 2)^{2} (x - 2)

(x + 2)^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 2, x = 2

z^{4} - 16 = 0

x^{4} - 20 x^{2} + 64 = 0

2 x^{4} + 5 x^{3} + 4 = x^{2}

x^{4} - 34 x^{2} + 225 = 0

x^{4} - 7 x^{2} + 6 = 0

What are the solutions to the equation x^3+2x^2-4x-8=0 ?
The solutions to the equation x^3+2x^2-4x-8=0 are x=-2,x=2
Find the zeros of x^3+2x^2-4x-8=0
The zeros of x^3+2x^2-4x-8=0 are x=-2,x=2