What are the solutions to the equation x^4-7x^2+6=0 ?

The solutions to the equation x^4-7x^2+6=0 are x=sqrt(6),x=-sqrt(6),x=1,x=-1

Find the zeros of x^4-7x^2+6=0

The zeros of x^4-7x^2+6=0 are x=sqrt(6),x=-sqrt(6),x=1,x=-1

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x^{4} - 7 x^{2} + 6 = 0

x = 6, x = - 6, x = 1, x = - 1

Solution steps

x^{4} - 7 x^{2} + 6 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 7 u + 6 = 0

Solve

u^{2} - 7 u + 6 = 0 : u = 6, u = 1

u = 6, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 6 : x = 6, x = - 6

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 6, x = - 6, x = 1, x = - 1

x^{3} - x^{2} - 4 x + 4 = 0

x^{3} = 30 3^{3} + 40 4^{3} + 50 5^{3}

x^{4} - 8 x^{2} + 7 = 0

x^{3} + 3 x^{2} - x - 3 = 0

x^{3} - 5 x^{2} - 4 x + 20 = 0

What are the solutions to the equation x^4-7x^2+6=0 ?
The solutions to the equation x^4-7x^2+6=0 are x=sqrt(6),x=-sqrt(6),x=1,x=-1
Find the zeros of x^4-7x^2+6=0
The zeros of x^4-7x^2+6=0 are x=sqrt(6),x=-sqrt(6),x=1,x=-1