What are the solutions to the equation x^4-8x^2+7=0 ?

The solutions to the equation x^4-8x^2+7=0 are x=sqrt(7),x=-sqrt(7),x=1,x=-1

Find the zeros of x^4-8x^2+7=0

The zeros of x^4-8x^2+7=0 are x=sqrt(7),x=-sqrt(7),x=1,x=-1

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x^{4} - 8 x^{2} + 7 = 0

x = 7, x = - 7, x = 1, x = - 1

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots, x = 1, x = - 1

Solution steps

x^{4} - 8 x^{2} + 7 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 8 u + 7 = 0

Solve

u^{2} - 8 u + 7 = 0 : u = 7, u = 1

u = 7, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 7 : x = 7, x = - 7

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 7, x = - 7, x = 1, x = - 1

x^{3} + 3 x^{2} - x - 3 = 0

x^{3} - 5 x^{2} - 4 x + 20 = 0

z^{4} = - 1

n^{3} = 16

4 x^{4} - 18 x^{2} = 0

What are the solutions to the equation x^4-8x^2+7=0 ?
The solutions to the equation x^4-8x^2+7=0 are x=sqrt(7),x=-sqrt(7),x=1,x=-1
Find the zeros of x^4-8x^2+7=0
The zeros of x^4-8x^2+7=0 are x=sqrt(7),x=-sqrt(7),x=1,x=-1