What are the solutions to the equation -x^3+5x^2-8x+4=0 ?

The solutions to the equation -x^3+5x^2-8x+4=0 are x=1,x=2

Find the zeros of -x^3+5x^2-8x+4=0

The zeros of -x^3+5x^2-8x+4=0 are x=1,x=2

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- x^{3} + 5 x^{2} - 8 x + 4 = 0

x = 1, x = 2

Solution steps

- x^{3} + 5 x^{2} - 8 x + 4 = 0

Factor

- x^{3} + 5 x^{2} - 8 x + 4 : - (x - 1) (x - 2)^{2}

- (x - 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = 2

x^{4} = 625

20 = [5 + \frac{0.12 x}{10}]^{20}

x^{4} - 4 x^{2} = 0

x^{4} - 3 x^{2} + 1 = 0

x^{3} = 729

What are the solutions to the equation -x^3+5x^2-8x+4=0 ?
The solutions to the equation -x^3+5x^2-8x+4=0 are x=1,x=2
Find the zeros of -x^3+5x^2-8x+4=0
The zeros of -x^3+5x^2-8x+4=0 are x=1,x=2