What are the solutions to the equation x^4-41x^2+400=0 ?

The solutions to the equation x^4-41x^2+400=0 are x=5,x=-5,x=4,x=-4

Find the zeros of x^4-41x^2+400=0

The zeros of x^4-41x^2+400=0 are x=5,x=-5,x=4,x=-4

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x^{4} - 41 x^{2} + 400 = 0

x = 5, x = - 5, x = 4, x = - 4

Solution steps

x^{4} - 41 x^{2} + 400 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 41 u + 400 = 0

Solve

u^{2} - 41 u + 400 = 0 : u = 25, u = 16

u = 25, u = 16

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 25 : x = 5, x = - 5

Solve

x^{2} = 16 : x = 4, x = - 4

The solutions are

x = 5, x = - 5, x = 4, x = - 4

w^{4} - 18 w^{2} + 81 = 0

9 x^{4} - 24 x^{3} + 16 x^{2} = 0

x^{6} - 26 x^{3} - 27 = 0

x^{3} - 5 x^{2} + 2 x + 8 = 0

x^{4} - 2 x^{2} = 2 x^{2}

What are the solutions to the equation x^4-41x^2+400=0 ?
The solutions to the equation x^4-41x^2+400=0 are x=5,x=-5,x=4,x=-4
Find the zeros of x^4-41x^2+400=0
The zeros of x^4-41x^2+400=0 are x=5,x=-5,x=4,x=-4