What are the solutions to the equation x^3-12x+16=0 ?

The solutions to the equation x^3-12x+16=0 are x=2,x=-4

Find the zeros of x^3-12x+16=0

The zeros of x^3-12x+16=0 are x=2,x=-4

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x^{3} - 12 x + 16 = 0

x = 2, x = - 4

Solution steps

x^{3} - 12 x + 16 = 0

Factor

x^{3} - 12 x + 16 : (x - 2)^{2} (x + 4)

(x - 2)^{2} (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 2, x = - 4

x^{3} + 2 x^{2} + 3 x + 6 = 0

x^{4} - 10 x^{2} + 29 = 8

x, x^{3} + y^{3} = 1

m^{3} = 64

4.7 x 1 0^{1} = 4.7 x^{10}

What are the solutions to the equation x^3-12x+16=0 ?
The solutions to the equation x^3-12x+16=0 are x=2,x=-4
Find the zeros of x^3-12x+16=0
The zeros of x^3-12x+16=0 are x=2,x=-4