What are the solutions to the equation z^3-27=0 ?

The solutions to the equation z^3-27=0 are z=3,z=-3/2+(3sqrt(3))/2 i,z=-3/2-(3sqrt(3))/2 i

Find the zeros of z^3-27=0

The zeros of z^3-27=0 are z=3,z=-3/2+(3sqrt(3))/2 i,z=-3/2-(3sqrt(3))/2 i

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z^{3} - 27 = 0

z = 3, z = - \frac{3}{2} + \frac{3 3}{2} i, z = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

z^{3} - 27 = 0

Move

27

to the right side

z^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

z = 3, z = - \frac{3}{2} + \frac{3 3}{2} i, z = - \frac{3}{2} - \frac{3 3}{2} i

- x^{3} + 6 x^{2} - 9 x + 4 = 0

x^{4} - 37 x^{2} + 36 = 0

x^{3} - 7 x + 12 = 0

y, y^{3} = x

x^{4} - 13 x^{2} + 37 = 7

What are the solutions to the equation z^3-27=0 ?
The solutions to the equation z^3-27=0 are z=3,z=-3/2+(3sqrt(3))/2 i,z=-3/2-(3sqrt(3))/2 i
Find the zeros of z^3-27=0
The zeros of z^3-27=0 are z=3,z=-3/2+(3sqrt(3))/2 i,z=-3/2-(3sqrt(3))/2 i