What are the solutions to the equation -x^3+2x^2+x-2=0 ?

The solutions to the equation -x^3+2x^2+x-2=0 are x=2,x=-1,x=1

Find the zeros of -x^3+2x^2+x-2=0

The zeros of -x^3+2x^2+x-2=0 are x=2,x=-1,x=1

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- x^{3} + 2 x^{2} + x - 2 = 0

x = 2, x = - 1, x = 1

Solution steps

- x^{3} + 2 x^{2} + x - 2 = 0

Factor

- x^{3} + 2 x^{2} + x - 2 : - (x - 2) (x + 1) (x - 1)

- (x - 2) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 2, x = - 1, x = 1

x^{3} + x + 2 = 0

x^{4} = x^{2}

x^{3} + x^{2} + 1 = 0

x^{3} - 2 x^{2} = 0

x^{3} + x^{2} - 5 x + 3 = 0

What are the solutions to the equation -x^3+2x^2+x-2=0 ?
The solutions to the equation -x^3+2x^2+x-2=0 are x=2,x=-1,x=1
Find the zeros of -x^3+2x^2+x-2=0
The zeros of -x^3+2x^2+x-2=0 are x=2,x=-1,x=1