What are the solutions to the equation 9x^4+27x^3-4x^2-12x=0 ?

The solutions to the equation 9x^4+27x^3-4x^2-12x=0 are x=0,x=-3,x=-2/3 ,x= 2/3

Find the zeros of 9x^4+27x^3-4x^2-12x=0

The zeros of 9x^4+27x^3-4x^2-12x=0 are x=0,x=-3,x=-2/3 ,x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{4} + 27 x^{3} - 4 x^{2} - 12 x = 0

x = 0, x = - 3, x = - \frac{2}{3}, x = \frac{2}{3}

Decimal Notation

x = 0, x = - 3, x = - 0.66666 \dots, x = 0.66666 \dots

Solution steps

9 x^{4} + 27 x^{3} - 4 x^{2} - 12 x = 0

Factor

9 x^{4} + 27 x^{3} - 4 x^{2} - 12 x : x (x + 3) (3 x + 2) (3 x - 2)

x (x + 3) (3 x + 2) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or 3 x + 2 = 0 or 3 x - 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions are

x = 0, x = - 3, x = - \frac{2}{3}, x = \frac{2}{3}

x^{3} - 9 x^{2} + 27 x - 27 = 0

2 x^{3} + 3 x^{2} = 8 x + 12

x^{3} - 8 = x - 2

(3^{3})^{2} = n^{6}

(x - 1) (x^{2} - 2) = (x - 1) (x - 2)

What are the solutions to the equation 9x^4+27x^3-4x^2-12x=0 ?
The solutions to the equation 9x^4+27x^3-4x^2-12x=0 are x=0,x=-3,x=-2/3 ,x= 2/3
Find the zeros of 9x^4+27x^3-4x^2-12x=0
The zeros of 9x^4+27x^3-4x^2-12x=0 are x=0,x=-3,x=-2/3 ,x= 2/3