What are the solutions to the equation 5x^4+2x-48=0 ?

The solutions to the equation 5x^4+2x-48=0 are x\approx 1.72765…,x\approx-1.79220…

Find the zeros of 5x^4+2x-48=0

The zeros of 5x^4+2x-48=0 are x\approx 1.72765…,x\approx-1.79220…

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5 x^{4} + 2 x - 48 = 0

x \approx 1.72765 \dots, x \approx - 1.79220 \dots

Solution steps

5 x^{4} + 2 x - 48 = 0

Find one solution for

5 x^{4} + 2 x - 48 = 0

using Newton-Raphson:

x \approx 1.72765 \dots

Apply long division:

\frac{5 x ^{4} + 2 x - 48}{x - 1.72765 \dots} = 5 x^{3} + 8.63826 \dots x^{2} + 14.92392 \dots x + 27.78335 \dots

5 x^{3} + 8.63826 \dots x^{2} + 14.92392 \dots x + 27.78335 \dots \approx 0

Find one solution for

5 x^{3} + 8.63826 \dots x^{2} + 14.92392 \dots x + 27.78335 \dots = 0

using Newton-Raphson:

x \approx - 1.79220 \dots

Apply long division:

\frac{5 x ^{3} + 8.63826 \dots x ^{2} + 14.92392 \dots x + 27.78335 \dots}{x + 1.79220 \dots} = 5 x^{2} - 0.32274 \dots x + 15.50235 \dots

5 x^{2} - 0.32274 \dots x + 15.50235 \dots \approx 0

Find one solution for

5 x^{2} - 0.32274 \dots x + 15.50235 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solutions are

x \approx 1.72765 \dots, x \approx - 1.79220 \dots

x^{4} + 8 x^{2} + 16 = 0

x, x^{3} y = - 4

x + 1.5 x^{2} + 9 x^{4} = 0

x, 8 x^{3} - y = 0

0 = \frac{1}{2} x^{3} - x

What are the solutions to the equation 5x^4+2x-48=0 ?
The solutions to the equation 5x^4+2x-48=0 are x\approx 1.72765…,x\approx-1.79220…
Find the zeros of 5x^4+2x-48=0
The zeros of 5x^4+2x-48=0 are x\approx 1.72765…,x\approx-1.79220…